Prova 1 2024 1 pdf

45cm x 90cm x 1,2cm σx σxy σxz σyx σy σyz σzx σzy σz -> tensor de tensões σx = -F1 / 90*1,2 = -540 / 108 = -5kN/cm² σy = -F2 / 45*1,2 = -540 / 54 = -10kN/cm² σyx = 180 / 54 = 3,33 kN/cm² [ -3,33 -10 0 -3,33 0 0 ] kN/cm² d = 30cm = 300mm = 0,3m h = 15cm = 15.000mm = 15m PONTA = 2 MPa TANGENCIAL = 0,06 MPa Aponta = π*d²/4 = π(0,3)²/4 = 7,0686*10⁻² cm² Alateral = 2π*h = 14,1372 m² 2*10⁶ Pa = F1 / 7,0686*10⁻² F1 = 141,371 N 0,06*10⁶ Pa = F2 / 14,1372 F2 = 848,632 N FR = F1 + F2 = 989,604 N FR = 989,604 kN 1520 γ = 0,00008 = tgθ = y/1520 γ = 0,1216 ε3 = Lf - Li / Li = 999,8784 - 1000 / 1000 ε3 = -0,0001216 mm/mm (b) ε1 = +0,000123 ε3 = -0,0001216