Exercicio 1 - Metodos Numericos

Métodos Numéricos Diagrama corpo livre ΣMe = 0 (f1) (F2) (900).(4,5) + (900.2,25) + F(3) = 0 4050 + 2025 + F.3 = 0 F = 2,025 kN Analisando A: ΣFx = 0 (FAD.) - FAB = 900 ΣFy = 0 (FAC.) - (FAD) = 0 Analisando B: ΣFx = 0 (FAB ) - (FA ) = 0 ΣFy = 0 FBD = 0 Analisando D: Σxx = Σyy = (FAB ) + (FFD ) = 0 Analisando E: Σx = 0 1800 - FEF = 0 FEF = 1800 N +1 ΣFy = 0 Ey - Fce = 0 Ey = F = 2,025 kN Analisando F: ΣFx = 0 (FFC ) FDF = - (FCCF ) - Fy = 0 Ex = 900 + 900 Ex = 1,8 kN Analisando C: ΣFx = 0 (F2) - (FCD) + (FCF) = 0 (FCF) - (FCD) = -900 ΣFy = 0 (FCE) - (FFC) (FCF) = 0 Ex = 1,8 kN F = 2,25 kN CAIO LIMA 256942 EDUARDO DEMO 232664 RAUL GASPEROTTO 223914 Scanned with CamScanner