Avaliação - Resistência dos Materiais 2022 1

Avaliação – Resistência dos Materiais Calcule as reações de apoio e ilustre os diagramas de esforço cortante e momento fletor. a) b) c) d) e) a 130 kN ΣFx=0 Ax = 0 kN Ax Ay By ΣMA=0 -30.8 + By.6 = 0 By = 30.8 / 6 By = 40 kN ↑ ΣFy=0 -30 + 40 + Ay = 0 Ay = 10 kN ↑ CORTANTE 30 30 -10 -10 V (kN) x (cm) A3 = A2 = 30.2 = 60 MOMENTO -60 M (kNm) x (m) Digitalizado com CamScanner Ax Ay By ΣFx=0 Ax=0 kN ΣMA=0 By.7 - 7.2.4 = 0 By = 7.2.4 / 7 By = 8 kN ↑ ΣFy=0 -7.2 + 8 + Ay = 0 Ay = 6 kN ↑ 6 - 7.2 - 8 CORTANTE 6 6 -8 -8 V (kN) x (cm) A1 = 6.3 = 18 A2 = 6.2 / 2.7 = 2,571 / 20,571 A3 = 8.2 / 2.7 = 1,428/2 A3 = 8.2 = 16 x = 3 + 6/7 = 3,8571 MOMENTO 3,8571 m 18 20,57143 36 M (kNm) x (cm) 60 40 45 ΣFx=0 Ax=0 kN ΣMA=0 45 - 40.5.5² / 2 + By.4 = 0 By = 500 / 4 By = 140 kN ↑ ΣFy=0 -60 - 40.5.5 + 140 + Ay = 0 Ay = 140 kN ↑ 40 - 60 = 80 80 - 40.4 = -80 -80 + By = 60 CORTANTE 80 -80 60 -80 V (kN) x (cm) A3: 80 = 80 A2: 80² / 2.40 = 80 45-80 = 35 35-80 = -45 MOMENTO -45 2m 35 -45 M (kNm) x (cm) Digitalizado com CamScanner 3 6 Ay Ax A ΣFx=0 (Ax=0 kN) ΣFy=0 Ay - 3.8 - 6 = 0 Ay = 30kN ΣMA=0 MA - 3.8*2 - 6*6 = 0 MA = 44 kN.m CORTANTE 30 qV(kN) -x(m) 6 MOMENTO -44 1(kN.m) x(m) Ay Ax e ΣFx=0 (Ax=0 kN) ΣMA=0 -1.4*2/2 - 1.2*6 - 2.9 + By*10 = 0 By = 2.42 ΣFy=0 -1.4 - 1.2 - 1 + 2.42 + Ay = 0 Ay = 3.78 Ay - 1.4 = -0.22 -0.22 - 1.2 = -1.42 -2.42 + By = 0 CORTANTE 3.78 - -0.22 -1.42 -2.42 1.2 x(m) V(kN) A1=3.78*2=7.1442 2-1 A2=0.22*2=0.0242 2-3 A3=0.22*2=0.44 A4=1.42*2=2.84 A5=2.42-1=2.42 MOMENTO 3.78m 7.1442 7.12 6.68 2.42 [m(kN.m)] x(m) X=3.78/1=3.78m Digitalizado com CamScanner